12x^2+88x+96=0

Solution for 12x^2+88x+96=0 equation:

12x^2+88x+96=0

a = 12; b = 88; c = +96;
Δ = b2-4ac
Δ = 882-4·12·96
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-56}{2*12}=\frac{-144}{24}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+56}{2*12}=\frac{-32}{24}
=-1+1/3
$